When ${\mathrm{KMnO}}_4$ reacts with acidified ${\mathrm{FeSO}}_4$

$2{\mathrm{KMnO}}_4 +8 {\mathrm{H}}_2{\mathrm{SO}}_4 +10 {\mathrm{FeSO}}_4 \to {\mathrm{K}}_2{\mathrm{SO}}_4+2{\mathrm{MnSO}}_4 +5 {\mathrm{Fe}}_2{\left({\mathrm{SO}}_4\right)}_3+8 {\mathrm{H}}_2\mathrm{O}$ ${\mathrm{KMnO}}_4$ is an oxidising agent, in acidic medium it oxidizes ${\mathrm{Fe}}^{2+} \mathrm{to} {\mathrm{Fe}}^{3+}$and ${\mathrm{KMnO}}_4$ itself get reduced.