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Q.

When ${NH}_{3}$ is treated with HCl, state of hybridization on central nitrogen

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a

Changes from ${sp}^{3} to {sp}^{2}$

b

Changes from ${sp}^{3} to sp$

c

Remains unchanged

d

Changes from ${sp}^{3} to {sp}^{3} d$

answer is B.

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Detailed Solution

${NH}_{3} + HCl \to {NH}_{4} Cl$

On ${NH}_{4}^{+}$ state of hybridization on central nitrogen atom is ${sp}^{3} as in {NH}_{3} .$

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When NH3 is treated with HCl, state of hybridization on central nitrogen