When NH4OH is added in Hg2NO32 solution, the ppt formed is:

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When ${NH}_{4} OH$ is added in ${Hg}_{2} {({NO}_{3})}_{2}$ solution, the ppt formed is:

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${Hg}_{2} O$

$Hg + HgO$

$2 Hg + HgO \cdot Hg ({NH}_{2}) {NO}_{3}$

$HgOHg ({NH}_{2}) {NO}_{3}$

answer is C.

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Detailed Solution

$2 {Hg}_{2}^{2 +} + {NO}_{3}^{-} + 4 {NH}_{3} + H_{2} O ⟶$

Not: $2 {Hg}^{2 +} + {NO}_{3}^{-} + 4 {NH}_{3} + H_{2} O ⟶$

$\underset{White ppt.}{\underset{⏟}{{HgO}_{g} \cdot Hg ({NH}_{2}) {NO}_{3} ↓}} + 3 {NH}_{4}^{+}$

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