When ${\mathrm{O}}_3$ is passed through an aqueous solution of $\mathrm{KI}$, the $\mathrm{pH}$ of the resulting solution is

 When ${\mathrm{O}}_3$ is passed through an aqueous solution of $\mathrm{KI}$, then $\mathrm{KI}$ is oxidised to iodine and water is reduced to hydroxide in which makes solution basic in nature. The pH of the solution will be (D) $10-14$.

$2\mathrm{KI}+{\mathrm{O}}_3+{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{KOH}}^{-}+{\mathrm{O}}_2+{\mathrm{I}}_2$