$\mathrm{When} {\mathrm{XeO}}_3 \mathrm{reacts} \mathrm{with} {\mathrm{XeOF}}_4, \mathrm{the} \mathrm{product} \mathrm{formed} \mathrm{is}$

$\text{ Going by the chemical reaction involved, we can easily tell the product. }$

(2) When ${\mathrm{XeO}}_3$ and ${\mathrm{XeOF}}_4$ react, the following chemical reaction takes place,

${\mathrm{XeO}}_3+{\mathrm{XeOF}}_4\to 2{\mathrm{XeO}}_2{ \mathrm{F}}_2$

The chemical reaction makes it obvious that the product given by this chemical reaction is $\mathrm{Xe}{\mathrm{O}}_2{\mathrm{ }\mathrm{F}}_2$

Hence, this option is correct.

(1) As we have mentioned in the above explanation, it can be very easily inferred that ${\mathrm{XeO}}_2{\mathrm{ }\mathrm{F}}_2$ is formed as a product of this reaction and not ${\mathrm{XeO}}_4$ . Hence, this option is incorrect.

(3) The above written chemical reaction tells us very clearly that ${\mathrm{XeOF}}_2$ is not formed out of this reaction. Instead, ${\mathrm{XeO}}_2{F}_2$ is formed as a result of this reaction. Hence, this option is incorrect.

(4) Xenon trioxy difluoride i.e. ${\mathrm{XeO}}_3{F}_2$ is not a product of this reaction. We can easily understand that the product of this reaction is ${\mathrm{XeO}}_2{\mathrm{ }\mathrm{F}}_2$ and not ${\mathrm{XeO}}_3{\mathrm{ }\mathrm{F}}_2$ . The geometry of this molecule is trigonal pyramidal in which the 2 fluorine atoms are attached on axial positions. Hence, this option is incorrect.

When ${\mathrm{XeO}}_3$ reacts with ${\mathrm{XeOF}}_4$ , the product formed is ${\mathrm{XeO}}_2{\mathrm{ }\mathrm{F}}_2$ . Hence, Option (2) is correct.