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Where must a 800 N weight be hung on a uniform horizontal 100 N pole of length L so that a boy at one end supports one-third as much as a man at the other end?

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An Intiative by Sri Chaitanya

at a distance of 0.22L from man

at a distance of 0.22L from boy

at a distance of 0.33L from man

in the middle

answer is A.

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Detailed Solution

$R_{M} + R_{B} = 900$

$\sum_{} τ_{man} = 0$

$\Rightarrow 800 x + 100 \frac{L}{2} - R_{B} L = 0$

Given, $R_{M} = 3 R_{B} . Solve to get x = 0.22 L$

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