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Where should and object be placed on the axis of a convex lens of focal length 8 cm, so as to achieve magnification of – 4 ? (Distances are measured from optic centre of the lens)

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– 6 cm

– 9 cm

– 12 cm

– 10 cm

answer is B.

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Detailed Solution

We know that, lens formula, $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$
Let say, $u = - x$

Magnification, $m = \frac{v}{u} = - 4$
$\Rightarrow v = + 4 x$
$∴ \frac{1}{+ 8} = \frac{1}{4 x} - \frac{1}{- x}$

$\Rightarrow x=10$

( - u because of sign convention)

$\Rightarrow u = - 10 c m$

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