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Where will the hand of a clock stop if it starts at 12 and makes $\frac{1}{2}$ of a revolution clockwise?

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answer is B.

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Detailed Solution

It is given the hand of a clock stop and it starts at 12 and makes

\frac{1}{2}

of a revolution clockwise.
A complete revolution of a clock’s hand is from 12 back to 12.
The clock’s hand makes a half revolution clockwise. So,

\frac{1}{2} \times 12 = 6

So, the hand moves by 6 from 12. Since 12 is the start point, we can consider it as 0,
0+6
Hence, it will stop at 6.
Hence option (2) is correct.

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