Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Where would an object be placed in a medium of refractive index μ1 , so that its real image is formed  equidistant from sphere of radius R and refractive index μ2 which is also placed in the medium of refractive index μ1 as shown in figure?

Question Image

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

μ2μ1μ2+μ1R

b

μ2μ2μ1R

c

μ1μ2μ1R

d

μ2+μ1μ2μ1R

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

In order to form the image at the same distance, the ray should emerge out of the sphere at the same angle as its incident angle. To obtain this, the ray should be parallel to the axis of the sphere as shown in the figure.


μ2+μ1x=μ2μ1R

x=μ1Rμ2μ1

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring