Q.

Where would an object be placed in a medium of refractive index μ1 , so that its real image is formed  equidistant from sphere of radius R and refractive index μ2 which is also placed in the medium of refractive index μ1 as shown in figure?

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a

μ2μ2μ1R

b

μ2μ1μ2+μ1R

c

μ2+μ1μ2μ1R

d

μ1μ2μ1R

answer is C.

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Detailed Solution

In order to form the image at the same distance, the ray should emerge out of the sphere at the same angle as its incident angle. To obtain this, the ray should be parallel to the axis of the sphere as shown in the figure.


μ2+μ1x=μ2μ1R

x=μ1Rμ2μ1

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Where would an object be placed in a medium of refractive index μ1 , so that its real image is formed  equidistant from sphere of radius R and refractive index μ2 which is also placed in the medium of refractive index μ1 as shown in figure?