Which is correct in the case of ${\left[Fe{\left(CN\right)}_6\right]}^{4-}$  complex

In $\left[Fe{\left(CN\right)}_6\right]{}^{4-}$, Fe is in +2 oxidation state and due to the presence of strong ligand, ${\mathrm{CN}}^{-}$  all 3d-electrons are paired and complex becomes diamagnetic. It is a low spin complex, therefore its hybridization is ${\mathrm{d}}^2{\mathrm{sp}}^3$ and have octahedral geometry.