AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

Which among the following groups of elements can be called Döbereiner's Triads?

Group A: Na, Si, Cl

Group B: Be, Mg, Ca

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

a

Group A only

b

Group B only

c

Both groups A and B

d

Neither group A nor group B

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

Both groups A and B are called the dobereiner's triad.
Döbereiner’s Triads are groups consisting of three elements (triads) that have similar chemical and physical properties. In every triad, the atomic weight of the middle element was half of the sum of the atomic weight of the other two elements. Properties of the middle element were also in the halfway of both the elements. Now, we will see whether the atomic mass of the middle element is average of the other two elements of the triads in the groups which are given to us.
Consider group A,
⇒

Atomic mass of Si = \frac{Atomic mass of Na + Atomic mass of Cl}{2}

\Rightarrow Atomic mass of Si = \frac{23 + 35.5}{2}

⇒

Atomic mass of Si = \frac{58.5}{2}

⇒

Atomic mass of Si = 29.25

⇒

Theoretical Atomic mass of Si = 28

As the calculated atomic mass is close to the theoretical atomic mass of Si, group A can form a Döbereiner’s Triad.
Similarly, now consider group B,

Atomic mass of Mg = \frac{Atomic mass of Be + Atomic mass of Ca}{2}

\Rightarrow Atomic mass of Mg = \frac{9 + 40}{2}

⇒

Atomic mass of Mg = \frac{49}{2}

⇒

Atomic mass of Mg = 24.5

⇒

Theoretical Atomic mass of Mg = 24

As the calculated atomic mass is close to the theoretical atomic mass of Mg, group B can form a Döbereiner’s Triad.

Watch 3-min video & get full concept clarity

courses

No courses found

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

best study material, now at your finger tips!

live classes
progress tracking
24x7 mentored guidance
study plan analysis

download the app

gplay

mentor

Download the App

gplay

personalised 1:1 online tutoring