Which among the following is/are correct about chromium ?

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Its electronic configuration is $3 d^{5} 4 s^{1}$

Total spin of chromium = 3

Spin multiplicity of 3d – subshell of chromium = 6

Magnetic moment of chromium $= \sqrt{48}$

answer is A, B, C, D.

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Detailed Solution

$C r_{24} \to 1 S^{2}, 2 S^{2} 2 P^{6}, 3 S^{2} 3 P^{6} 3 d^{5} 2 s^{1}$

Total spin = Number of unpaired

$electrons × \frac{1}{2} = 6 \times \frac{1}{2} = 3$

Spin multiplicity $= \sqrt{n (n + 2)}$ , where n = number of unpaired electrons

$= \sqrt{6 \times 8} = \sqrt{48} B . M$

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