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Which among the following metal target called anti cathode when place in the path of cathode rays will emit x-rays of highest frequency?

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answer is C.

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Detailed Solution

Mosely's equation, √v = a(z - b).

√v ∝ z, greater the atomic number of the metal anti cathode greater will be the frequency of x - ray emitted z of Pt > Cd > Pd > Zn.

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