Which amongst the following options is correct graphical representation of Boyle's Law?

At constant temperature,
This was proved by the graph 3.
(1) Boyle’s Law P = k/v (T = constant)
P = k x 1/v obeys
y = mx equation
The graph P on y-axis and 1/v on x-axis is a straight line passing through origin.

(2) It represents Gay Lussac’s Law:
statement:
Pressure of a fixed mass of a gas is directly proportional to absolute temperature at constant volume.
P α T (n,v = constant)

From the graph, slope order is
$\begin{array}{r}{\theta }_1<{\theta }_2<{\theta }_3\\ \text{ Slope }\Rightarrow K=\frac{nR}{V}\\ \frac{nR}{V_3}<\frac{nR}{V_2}<\frac{nR}{V_1}\\ \therefore \frac{1}{V_3}<\frac{1}{V_2}<\frac{1}{V_1}\end{array}$
(4) Boyle’s Law P = k/v (T = constant)
P = k x 1/v obeys
y = mx equation
The graph P on y-axis and 1/v on x-axis is a straight line passing through origin.

From the graph,
slope order is
$$\begin{gathered} {\theta }_1<{\theta }_2<{\theta }_3 \\ \begin{array}{l}\text{ Slope }\Rightarrow \mathrm{K}=\mathrm{nRT}\\ {\mathrm{nRT}}_1<{\mathrm{nRT}}_2<{\mathrm{nRT}}_3\\ \therefore {\mathrm{T}}_1<{\mathrm{T}}_2<{\mathrm{T}}_3\end{array} \end{gathered}$$