Which cation forms an insoluble chloride and an insoluble sulphide?

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${Cu}^{2} +$

${Mn}^{2} +$

${Ba}^{2} +$

${Pb}^{2} +$

answer is D.

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Detailed Solution

Lead(II) forms an insoluble chloride as well as an insoluble sulphide.

Water is strongly attracted to the chloride anion because of its high electronegativity and high charge/radius ratio. As a result, even if water molecules are drawn to one another and "locked," the contract does not provide enough energy to significantly outweigh the lattice energy.

Lead typically attaches to sulfur in the form of sulfide $(S^{2} -)$ or to phosphor in the form of phosphate Lead $({PO}_{4}^{3} -)$ particularly soluble in none of these forms, although it does exist in the environment as immobile compounds.