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Q.

Which complex has square planar structure?

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a

Ni(CO)4

b

[NiCl4]2–

c

[Ni(H2O)6]2+

d

[Cu(NH3)4]2+

answer is D.

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Detailed Solution

In [Cu(NH3)4]2+, the oxidation state of Cu is +2 and the 3d-subshell has 9 electrons. As ammonia is a strong ligand, it moves the unpaired electron from 3d and placed in last orbital of 4p of Cu. In this way, the complex achieves dsp2 hybridization and complex has square planar geometry.

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