Q.

Which compound below can show geometrical isomerism?

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a

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b

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c

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d

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answer is D.

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Detailed Solution

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Conclusion:

→ In order to exhibit geometrical isomerism, double bonded carbon should possess two different groups.

→ The C1 carbon two groups and C2 carbons two groups may (or) may not be same.

→ Either C1 carbon two groups (or) C2 carbon two groups are identical then geometrical isomerism is not possibel.

→ If all the four groups are different [a,b,c,d], then they donot exhibit CIS, trans isomerism but they exhibit geometrical isomerism i.e., E, Z-isomerism

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