Which criteria of congruence of triangles will you use to show that$△\mathrm{PRQ}\cong △\mathrm{XYZ} \mathrm{if} \mathrm{you} \mathrm{are} \mathrm{given} \mathrm{XZ}=\mathrm{PR},\mathrm{QR}=\mathrm{YZ} \mathrm{and} \angle \mathrm{PRQ}=\angle \mathrm{XZY}$

In$△\mathrm{PRQ} \mathrm{and} △\mathrm{XYZ} \mathrm{we} \mathrm{are} \mathrm{given} \mathrm{that} \mathrm{XZ}=\mathrm{PR},\mathrm{QR}=\mathrm{YZ} \mathrm{and} \angle \mathrm{PRQ}=\angle \mathrm{XZY}$

From the figure,$\angle PRQ$ lies in between side PR and side QR and $\angle XZY$ lies between side XZ and side YZ and PR = XZ, QR = YZ.

$\therefore$ By SAS criteria of congruency$△PRQ\cong △XYZ$