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Q.

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?

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a

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b

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c

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d

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answer is C.

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Detailed Solution

According to the question we get, 

let us take the acceleration to be a negative constant, 

a = -B

now we know  a = dvdt

dvdt= -B

dvdt=dxdtxdvdx = - B but dxdt= v now we get,  v dvdx=-B rearraging the above we get,  vdv = -Bdx no integrating both sides with 0 - v and limits of distance 0 - x 0vvdv = 0xdx after integration we get v220v = -Bx0x + C  ( c  is the constant ) v22=-Bx+c x = -v22B+cB  

 

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