Which has maximum number of atoms?

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108 g of Ag(108)

27 g of Al(27)

24 g of C(12)

56 g of Fe(56)

answer is A.

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Detailed Solution

24 g of carbon has maximum number of atoms. i.e. $12.046 \times 10^{23} a t o m s$ .

$N o . o f a t o m s (N) = \frac{G i v e n m a s s (m)}{G i v e n a t o m i c m a s s (M)} \times A v a g a d r o N o . (N_{A})$

1) $N_{C} = \frac{24}{12} \times N_{A} = 2 N_{A}$

2) $N_{F e} = \frac{56}{56} \times N_{A} = 1 N_{A}$

3) $N_{A l} = \frac{27}{27} \times N_{A} = 1 N_{A}$

4) $N_{A g} = \frac{108}{108} \times N_{A} = 1 N_{A}$

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