Which has maximum number of equivalents per mole of the oxidant ?

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$I^{-} (aq) + {IO}_{3}^{-} (aq) \overset{}{\to} I_{3}^{-} (aq)$

$Ag (s) + {NO}_{3}^{-} (aq) \overset{}{\to} {NO}_{2} (g) + {Ag}^{+} (aq)$

$Mg (s) + {VO}_{4}^{3 -} (aq) \overset{}{\to} {Mg}^{2 +} (aq) + V^{2 +} (aq)$

$Zn (s) + {VO}_{}^{2 +} (aq) \overset{}{\to} V^{3 +} (aq) + {Zn}^{2 +} (aq)$

answer is A.

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Detailed Solution

Oxidant is the oxidizing agent (which has been reduced)

(1) $\overset{+ 5}{I} O_{3}^{-} \to {\overset{0}{I}}_{2}; Change in ox . state = 5 = no . of equivalents per mole .$

(2) $\overset{+ 5}{N} O_{3}^{-} \to \overset{+ 4}{N} O_{2}; Change in ox . state = 1$

(3) $\overset{+ 5}{V} O_{4}^{- 3} \to V^{+ 2}; change in ox . state = 3$

(4) $\overset{+ 4}{V} O^{+ 2} \to V^{+ 3}; change in ox . state = 1$

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