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Q.

Which has minimum number of oxygen atoms ?

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a

10mL $H_{2} O (l)$

b

0.1 mole of $V_{2} O_{5} (s)$

c

12gm $O_{3} (g)$

d

$12.044 \times 10^{22} m o l e c u l e s o f C O_{2}$

answer is D.

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Detailed Solution

$12.044 \times 10^{22} m o l e c u l e s o f C O_{2} = 0.2 m o l e s 0.2 \times 2 \times N_{A} O - a t o m s$

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