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Q.

Which has the largest number of molecules?

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a

54 g of N2O5

b

46 g of C2H5OH

c

36 g of H2O

d

28 g of CO2

answer is C.

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Detailed Solution

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To compare the number of molecules for each substance, we'll first need to calculate the number of moles of each substance. Then, using Avogadro's constant (6.022×1023 molecules per mole), we can determine the number of molecules in each sample.

  •  N2O5

Number of moles of N2O5 = 54 g / 108.01 g/mol ≈ 0.5 moles

Number of molecules of N2O5 = Number of moles * Avogadro's constant
Number of molecules of N2O5 ≈ 0.5 moles * (6.022 x 1023 molecules/mol)

 ≈ 3.011 x 1023 molecules

  •  CO2

Number of moles of CO2 = 28 g / 44.01 g/mol ≈ 0.636 moles

Number of molecules of CO2 = Number of moles * Avogadro's constant
Number of molecules of CO2 ≈ 0.636 moles * (6.022 x 1023 molecules/mol)

≈ 3.834 x 1023 molecules

  •  H2O

Number of moles of  H2O = 36 g / 18.02 g/mol ≈ 1.997 moles

Number of molecules of  H2O = Number of moles * Avogadro's constant
Number of molecules of  H2O ≈ 1.997 moles * (6.022 x 1023 molecules/mol)

 ≈ 1.202 x 1024 molecules

  • C2H5OH

Number of moles of C2H5OH = 46 g / 46.08 g/mol ≈ 0.998 moles

Number of molecules of C2H5OH = Number of moles * Avogadro's constant
Number of molecules of C2H5OH ≈ 0.998 moles * (6.022 x 1023 molecules/mol) 

≈ 6.012 x 1023 molecules

Comparing the number of molecules:

- 54 g of N2O5 ≈ 3.011 x 1023 molecules
- 28 g of CO2 ≈ 3.834 x 1023 molecules
- 36 g of H2O ≈ 1.202 x 1024 molecules
- 46 g of C2H5OH ≈ 6.012 x 1023 molecules

Hence, 36 g of H2O has the largest number of molecules among the given substances.

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