Which hybridisation is found in HClO₄ and HClO₃ ?

HClO₄ : no. of hybrid orbitals formed=$\frac{1}{2}\left(7+1\right)=4\to {\mathrm{sp}}^3\mathrm{hybridization}.$

and HClO₃ : no. of hybrid orbitals formed=$\frac{1}{2}\left(7+1\right)=4\to {\mathrm{sp}}^3 \mathrm{hybridization}$