Which hybridisation is found in NH₃ and H₂O ?

No. of hybrid orbitals(H.O) formed=$\frac{1}{2}(\mathrm{V}+\mathrm{M}-\mathrm{Charge})$

where, V= no. of valence electrons of central atom

M=no. of monovalent atoms.

NH₃ : no. of H.O = $\frac{1}{2}\left(5+3\right)=4\to {\mathrm{sp}}^3 \mathrm{hybridization}.$

H₂O : no. of H.O = $\frac{1}{2}\left(6+2\right)=4\to {\mathrm{sp}}^3 \mathrm{hybridization}$