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Q.

Which hybridisation is found in ${HClO}_{4}$ and ${HClO}_{3} ?$

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a

${sp}^{3}$

b

${sp}^{2}$

c

$sp$

d

${dsp}^{2}$

answer is A.

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Detailed Solution

In HClO₄No. of hybrid orbitals =1/2 [7+1 +0+0] =4 =SP³

In HClO₃ No. of hybrid orbitals =1/2 [7+1 +0+0] =4 =SP³

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