Which is correct statement about the electrolysis of aqueous solution of CuSO₄ with copper cathode and Pt anode?

$$\begin{gathered} \mathrm{Anode} 2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)⟶4{\mathrm{H}}^{+}(\mathrm{aq}.)+{\mathrm{O}}_2\left(\mathrm{g}\right)+4{\mathrm{e}}^{-} \\ \mathrm{Cathode}{\mathrm{Cu}}^{+2}+2{\mathrm{e}}^{-}\rightleftharpoons \mathrm{Cu}\left(\mathrm{s}\right) \end{gathered}$$
As number of OH^- ions decreases hence H⁺ increases so pH of solution decreases, Number of Cu²⁺ ions decreases so blue colour intensity decreases during electrolysis.