Q.

Which is the correct sequence in the following properties? For the correct order mark (T) and for the incorrect order mark (F):
(A) Lewis acidity order : SiF4 < SiCl4 < SiBr4 < SiI4
(B) Melting point : NH3 > SbH3 > AsH3 > PH3
(C) Boiling point : NH3 > SbH3 > AsH3 > PH3
(D) Dipole moment order : NH3 > SbH3 > AsH3 > PH3

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a

FFTT

b

FTFT

c

TFTF

d

 FFTF 

answer is A.

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Detailed Solution

(A) (F); As the size of halogen atom increases crowding on Si atom will increase, hence, tendency of attack of Lewis base decreases.
(B) (T); M.P. of NH3 is highest due to intermolecular H-bonding in it.
Next lower M.P. will be of SbH3 followed by AsH3 due to high mol. wt. of SbH3.
(C) (F);M.P. and B.P. of increase from PH3 to SbH3 via AsH3 due to increase in mol.wt.NH3 does not follow this trend due to intermolecular H-bonding.
Increasing B.P. order : PH3 < AsH3 < NH3 < SbH3
(D) (T); Value of bond moment decreases.

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