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Q.

Which is the greatest 4-digit perfect square?

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a

9998

b

9901

c

9999

d

9801

answer is B.

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Detailed Solution

detailed_solution_thumbnail

Greatest number of 4-digits = 9999. We find 9999 by long division

method. The remainder is 198. This shows 992

 is less than 9999 by 198.

This means if we subtract the remainder from the number, we get a perfect square.

Therefore, the required perfect square is 9999 – 198 = 9801.

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