Which is/are in linear shape?

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${NO}_{2}^{+}$

${XeF}_{2}$

$I_{3}^{-}$

$I_{3}^{+}$

answer is A, B, C.

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Detailed Solution

Although $N O_{2}$ is a bent molecule, when you remove an electron from it, creating it ${NO}_{2}^{+}$ , the molecule becomes linear due to the loss of a lone electron. The two O atoms and the single electron on the center atom in ${NO}_{2}^{+}$ are not in repulsion with one another.

With five pairs of electrons around Xe in ${XeF}_{2}$ , the structure is trigonal bipyramidal. The three lone pairs are located at the equator, whereas the fluorine atoms are in linear places. A linear molecule is ${XeF}_{2}$ .

The molecular geometry of $I_{3}^{-}$ - is linear. Despite having three iodine atoms, one of them has a negative charge, which results in three lone pairs of electrons and two bond pairs.

Hence ${NO}_{2}^{+}$ , ${XeF}_{2}$ and $I_{3}^{-}$ are in linear shape

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