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Q.

Which mixture forms a buffer when dissolved in 1 L of water?

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a

0.5 mol NH3+ 0.5 mol HCl

b

0.2 mol NaOH + 0.2 mol HBr   

c

0.2 mol NaCl + 0.2 mol HCl

d

0.4 mol HNO2 + 0.2 mol NaOH

answer is C.

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Detailed Solution

Since weak acid is in excess buffer solution is formed as follows

 HNO2+NaOH→NaNO2 +H2O
 (weak acid)(strong base)       (salt)
mole0.40.2         0             0
t=t∞0.4 - 0.2 = 0.20.2 - 0.2 = 0      0.2             0

The resultant solution contains a weak acid & its salt forming an acidic buffer.

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