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Which mixture forms a buffer when dissolved in 1 L of water?

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0.5 mol NH₃+ 0.5 mol HCl

0.2 mol NaOH + 0.2 mol HBr

0.2 mol NaCl + 0.2 mol HCl

0.4 mol HNO₂ + 0.2 mol NaOH

answer is C.

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Detailed Solution

Since weak acid is in excess buffer solution is formed as follows

	HNO₂	+NaOH	$\to$ NaNO₂ +H₂O
	(weak acid)	(strong base)	(salt)
mole	0.4	0.2	0 0
$t = t_{\infty}$	0.4 - 0.2 = 0.2	0.2 - 0.2 = 0	0.2 0

The resultant solution contains a weak acid & its salt forming an acidic buffer.

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