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Q.

Which of following is true presentation of unit of silicate  9/4 oxygen shared per tetrahedra in double chain silicate?

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a

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b

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c

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d

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answer is B.

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Detailed Solution

Consider the give structure present in option 2 where the red dots shows the number of oxygen atoms shared by per tetrahedral unit of the given silicate.

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In the above image, there are four tetrahedral units, out of which three tetrahedral units shared two O atoms and one tetrahedral unit shares 3 oxygen atoms. The average number of O atoms shared by each tetrahedral unit is calculated as:

Average number of O atoms=2+2+2+34 =94

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