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Which of the elements possess only one electron in 5d-orbital.

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La, Lu

Pr, Lu

Tm, Pm

La, Pm

answer is D.

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Detailed Solution

$La (57) : [xe] 5 d^{1} 6 s^{2}$

$Lu (71) : [xe] 4 f^{14} 5 d^{1}$

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