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Which of the fdllowing complex ions is expected to absorb visible light
$(At. no. Zn = 30, Sc = 21, Ti = 22, Cr = 24)$

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${[Sc {(H_{2} O)}_{3} {({NH}_{3})}_{3}]}^{3 +}$

${[{Ti(en)}_{2} {({NH}_{3})}_{2}]}^{4 +}$

${[Cr {({NH}_{3})}_{6}]}^{3 +}$

${[Zn {({NH}_{3})}_{6}]}^{2 +}$

answer is C.

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Detailed Solution

${Cr}^{3 +}$ in the complex has unpaired electrons in the

d orbital.

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