Which of the following are the correct reactions to prepare the compounds?

(A) $2{\mathrm{BeCl}}_2+{\mathrm{LiAlH}}_4\to 2{\mathrm{BeH}}_2+\mathrm{LiCl}+\mathrm{A}l{\mathrm{Cl}}_3$
(B)$\mathrm{BeO}+\mathrm{C}+{\mathrm{Cl}}_2\stackrel{600-800\mathrm{K}}{\rightleftarrows }{\mathrm{BeCl}}_2+\mathrm{CO}$
(C)$2\mathrm{Li}+{\mathrm{C}}_2{\mathrm{H}}_2\to {\mathrm{Li}}_2{\mathrm{C}}_2+{\mathrm{H}}_2$
(D)$\mathrm{Be}+{\mathrm{O}}_2\to {\mathrm{BeO}}_2$

The correct answer is

Since Lithium has high value of ionization energy , hence it doesn't form compound with acetylene.

Beryllium and magnesium are kinetically inert to oxygen and water because of the formation of an oxide film on their surface. However, powdered beryllium burns brilliantly on ignition in air to give BeO and Be₃N₂