Which of the following best shows the construction of a triangle PQR in which QR = 5 cm, ∠Q = 60°, and PR–PQ = 3cm?

The steps to draw the triangle of the given measurement are as follows:

1. Draw a line segment of base QR = 5 cm

2. Measure and draw ∠Q = 60° and let the ray be QM.

3. Take a compass and measure PR–PQ = 3cm.

4. Since PR–PQ is given, we will extend the ray downwards.

5. With Q as the centre, draw an arc at point S on the ray QM.

6. Join SR.

7. Now draw the perpendicular bisector of the line SR and the intersection point is taken as P.

8. Now join PR.

9. Therefore, PQR is the required triangle.