Which of the following boiling point order is correct?

Since helium only contains one spherical atom, it has a lower boiling point. It is not very polarizable and has a relatively small surface area. A diatomic molecule of elemental hydrogen is present (${\mathrm{H}}_2$).

As molecular weight increases, B.P. increases. Thus, the correct order is,

$\mathrm{He}<{\mathrm{D}}_2<{\mathrm{T}}_2$.

Hence, the correct option is D.