Which of the following complex will produce maximum amount of $AgCl$ (ppt.) on reaction with excess of ${AgNO}_{3}$ ?

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${PtCl}_{2} \cdot 2 {NH}_{3}$

${PtCl}_{2} \cdot 4 {NH}_{3}$

${CoCl}_{3} \cdot 4 {NH}_{3}$

${PtCl}_{2} \cdot 2 HCl$

answer is A.

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Detailed Solution

Since one mole of $P t (N H_{3})_{4} C l_{2} N H_{3}$ reacts with two moles of excess $A g N O_{3}$ to produce two mole of white precipitate which is maximum. The compound is $P t (N H_{3})_{4} C l_{2} N H_{3}$ .

$P t (N H_{3})_{4} C l_{2} + 2 A g N O_{3} \to 2 A g C l + P t (N O_{3})_{2} + 4 N H_{3}$

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