Which of the following compound having number of $\mathrm{p\pi }-\mathrm{p\pi }$ bond is equal to $\mathrm{p\pi }-\mathrm{d\pi }$ bonds?

A lone pair and two bond pairs (due to sigma bonding) are present in these hybrid orbitals as a result of the sulphur atom's${\mathrm{sp}}^2$hybridization. In pi bonding, 3p unpaired electrons and 3d hybridised orbitals are combined with 2p unhybridized oxygen orbitals. As a result, two pi bonds—the $\mathrm{p\pi }-\mathrm{p\pi }$ and $\mathrm{p\pi }-\mathrm{d\pi }$bonds—are created.