Q.

Which of the following contains the maximum number of atoms?

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a

1.8g of C6H12O6

b

10g of CaCO3

c

9g of NH4NO3

d

4g of hydrogen

answer is B.

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Detailed Solution

Maximum No. of atoms =wGMWt×NA×No. of atoms

Maximum No of CaCO3 atoms=10100×NA×5=0.5NA

Maximum No. of H atoms in 4g H2=42×NA×2=4NA

Maximum No. of in   NH4NO3=980×NA×9=1.01NA

Maximum No.of C6H12O6atoms C6H12O6=1.80180×NA×24=0.24NA

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Which of the following contains the maximum number of atoms?