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Which of the following contains the maximum number of atoms?

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10g of CaCO₃

4g of hydrogen

9g of NH₄NO₃

1.8g of C₆H₁₂O₆

answer is B.

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Detailed Solution

1^st Option

GFW of CaCO₃ = 100g

Atomicity = 5

100g of CaCO₃, 5N_A atoms

10g of CaCO₃ 'X₁' atoms

large X_1 = frac{10}{100} times 5N_A = frac{N_A}{10}

2^nd option

GAW of Hydrogen = 1g

1g of Hydrogen contain N_A atoms

4g of Hydrogen contain 'X₂' atoms

X₂ = 4N_A

3^rd option

GFW of NH₄NO₃ = 80g

Atomicity = 9

80g of NH₄NO₃ contain 9N_A atoms

9g of NH₄NO₃ contain 'X₃' Atoms

large X_3 = frac{9 times 9}{80} N_A approx N_A

4^th option

GMW of C₆H₁₂O₆ = 180g

Atomicity = 18

180g of C₆H₁₂O₆ contains 18N_A atoms

1.8g of C₆H₁₂O₆ contains 'X₄' atoms

large X_4 = frac{1.8}{180} times 18N_A = 0.18 N_A

Maximum number of atoms are present in 4g of Hydrogen

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