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Q.

Which of the following elements would be chemically similar to the atom which has electronic configuration of $2, 8, 7$ ?

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a

N (7)

b

F (9)

c

P (15)

d

Ar (18)

answer is B.

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Detailed Solution

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$F (9)$ would be chemically similar to the atom which has electronic configuration of $2, 8, 7$ .
The given electronic configuration of the element is $2, 8, 7$ , and it shows that this element has $7$ valence electrons in its atoms.
The atomic number of N is $7$ , so the electronic configuration is $2, 5$ . The atomic number of F is $9$ , so the electronic configuration is $2, 7$ .
The atomic number of P is $15$ , so the electronic configuration is $2, 8, 5$ .
Finally, the atomic number of Ar is $18$ , so the electronic configuration is $2, 8, 8$ . We can see that fluorine has $7$ valence electrons, just like the given element.

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