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Q.

Which of the following equations has $\frac{1}{5}$ as a root

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a

35 x^{2} - 2 x - 1 = 0

b

2 x^{2} - 7 x + 6 = 0

c

10 x^{2} - 3 x - 1 = 0

d

35 x^{2} + 12 x + 1 = 0

answer is A.

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Detailed Solution

Substitute

\frac{1}{5}

in every quadratic equation if the result is zero then it is a root of that

$35 x^{2} - 2 x - 1 = 35 {(\frac{1}{5})}^{2} - 2 (\frac{1}{5}) - 1 = \frac{35}{25} - \frac{2}{5} - 1 = 0$

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