Which of the following expressions correctly represents the equivalent conductance at infinite dilution. Given that ${λ^{0}}_{A l^{+ 3}}$ and ${λ^{0}}_{S {O_{4}}^{2 -}}$ are the equivalent conductances at infinite dilution of respective ions.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$2 λ_{A l_{}^{+ 3}}^{0} + 3 λ_{S O_{4}^{2 -}}^{0}$

$λ_{A l_{}^{+ 3}}^{0} + λ_{S O_{4}^{2 -}}^{0}$

$(λ_{A l_{}^{+ 3}}^{0} + λ_{S O_{4}^{2 -}}^{0}) \times 6$

$\frac{1}{3} λ_{A l_{}^{+ 3}}^{0} + \frac{1}{2} λ_{S O_{4}^{2 -}}^{0}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$λ_{M}^{0} A l_{2} {(S O_{4})}_{3} \to 2 \times λ_{M}^{0} A l^{+ 3} + 3 λ_{M}^{0} {(S O_{4})}_{3}$

$\begin{array}{l} λ_{M}^{0} {Al}_{2} {({SO}_{4})}_{3} = λ_{e q}^{0} A l_{2} {({SO}_{4})}_{3} \times n - factor \\ λ_{e q}^{0} {Al}_{2} {({SO}_{4})}_{3} = \frac{2 \times λ_{M}^{0} A l^{+ 3} + 3 λ_{M}^{0} (S O_{4}^{2 -})}{6} \\ = \frac{6}{6} \times λ_{e q}^{0} A l^{+ 3} + \frac{6}{6} λ_{e q}^{0} (S O_{4}^{2 -}) \\ λ_{e q}^{0} {Al}_{2} {({SO}_{4})}_{3} = λ_{e q}^{0} A l^{+ 3} + λ_{e q}^{0} (S O_{4}^{2 -}) \end{array}$