Q.




Which of the following gives the relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (– 3, 4)?

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a

3x - 2y +5 =0

b

3x + 2y -5 =0

c

3x + y -5 =0

d

3x - y +5 =0 

answer is C.

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Detailed Solution

Given that the point (x, y) is equidistant from the point (3, 6) and (– 3, 4).
Let the points be A(3,6), B(-3,4) and P(x, y).
We know that the distance between 2 points ( x 1 , y 1 ),( x 2 , y 2 )  is given by
D= ( x 2 x 1 ) 2 + ( y 2 y 1 ) 2  
Using distance formula between AP,
AP = = (x3) 2 + (y6) 2 (1)  
For distance BP,
BP = = (x(3)) 2 + (y4) 2 ............(2)  
Given that AP = BP. So,
Question Image
The relation between x and y is given by the equation 3x + y -5 =0.
Therefore, the correct option is 3.
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Which of the following gives the relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (– 3, 4)?