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Which of the following gives two oxygen-acids when dissolved in water ?

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$N_{2} O$

$N_{2} O_{3}$

$N_{2} O_{4}$

$N_{2} O_{5}$

answer is C.

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Detailed Solution

$N_{2} O_{4}$ remains in equilibrium with $N O_{2}$

Following is the hydrolysis reaction

$N O_{2} + H_{2} O \to H N O_{2} + H N O_{3}$

Thus, it is a mixed anhydride.

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