Which of the following group of fractions are proper fractions?

We know that a proper fraction is a fraction where the numerator is less than the denominator.

Let us check all the options one by one:

1. $\frac{1}{2},\frac{2}{3},\frac{3}{4}$

Here in all fractions, the numerator is less than the denominator.

Therefore, all the fractions in the group are proper fractions.

2. $1,1,1$

1 can be written as $\frac{1}{1}$ and its denominator is the same as the numerator, which does not satisfy the condition for proper fractions.

Therefore, all the fractions in the group are not proper fractions.

3. $\frac{1}{2},1,\frac{3}{2}$

In $\frac{3}{2}$, the numerator 3 is greater than the denominator 2.

Therefore, all the fractions in the group are not proper fractions.

4. $\frac{1}{2},\frac{3}{2},\frac{4}{6}$

In $\frac{3}{2}$, the numerator 3 is greater than the denominator 2.

Therefore, all the fractions in the group are not proper fractions.

Therefore,$\frac{1}{2},\frac{2}{3},\frac{3}{4}$ is the correct alternative.