Which of the following has a square planar geometry?

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${[{FeCl}_{4}]}^{2 -}$

${[{NiCl}_{4}]}^{2 -}$

${[{PdCl}_{4}]}^{2 -}$

${[{CoCl}_{4}]}^{2 -}$

answer is C.

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Detailed Solution

It is given to find out the compound which has a square planar geometry.

The nature of the ligand affects the hybridization of the compound which in turn affects the geometry.

Explanation

In ${[{PdCl}_{4}]}^{2 -}$ , the oxidation state of Pt is +2. So, the electronic configuration is $5 d^{8}$ .
Six electrons are paired and two remain unpaired in the ground state.

${Cl}^{-}$ is a weak ligand, yet it causes electron pairing in 5d, opening up one 5d orbital. This results in ${dsp}^{2}$ hybridization and square planar geometry.

Hence the correct answer is C) ${[{PdCl}_{4}]}^{2 -}$