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Q.

Which of the following inequalities holds true with respect to the given figure?

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a

OB > OA

b

OA < OD

c

AC > AB

d

EO > EB

answer is B.

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Detailed Solution

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Applying the angle sum property of triangles in ΔBDC:

CBD = 180° – (90° + 60°) = 30°

Applying the angle sum property of triangles in ΔAEC:

EAC = 180° – (90° + 60°) = 30°

Also, A = 70°

∴ ∠BAO = ÐA – ÐEAC = 70° – 30° = 40°

Applying the angle sum property of triangles in ΔABD:

ABD = 180° – (90° + 70°) = 20°

Applying the angle sum property of triangles in ΔOBE:

BOE = 180° – (90° + 30°) = 60°

We know that in a triangle, the side opposite to the larger angle is longer.

Now let us check each option one by one.

Option:

Consider ΔBOE

Here, EOB = 60° and EBO = 30°

EO < EB

Option:

Consider ΔOAB

OAB = 40° and OBA = 20°

OB > OA

Option :

Consider ΔODA

Here, ODA = 90° and OAD = 30°

OA > OD

Option :

Consider ΔABC

Here, ABC = 50° and ACB = 60°

AC < AB

Hence, the relation OB > OA is the correct alternative.

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Which of the following inequalities holds true with respect to the given figure?