Which of the following ions does not involve p$\mathrm{\pi }$ — d$\mathrm{\pi }$ bonding?

(1) The S-atom in the excited state (3s²3p³3d¹ ) has sp³ hybridization (sp³)² (sp³)¹ (sp³)¹(sp³)¹3d¹
The three hybrid orbitals form three (S-O) $\mathrm{\sigma }$ -bonds and the 3d pure orbital gives (S-O) $\mathrm{\pi }$-bond.
(2) In ${\mathrm{PO}}_4^{3-}$, P-atom in its excited state $\left(3s^{1}3p^{3}3d^1\right)$ is sp³ hybridized. Four hybrid orbitals forms (P-O) $\mathrm{\sigma }$ -bonds whereas 3d¹ gives (P-O)  $\mathrm{\pi }$-bond.

(3) In ${\mathrm{NO}}_3^{-}$ N-atom is sp² hybridized as ${\left(s{p}^2\right)}^2{\left(s{p}^2\right)}^1{\left(s{p}^2\right)}^{1}2p_z^1$ 

Completely filled sp’ hybrid orbital on N-atom donates an electron pair to the vacant 2p orbital of O atom to form dative bond. Other two hybrid orbitals form (N-O) $\mathrm{\sigma }$-bonds. The pure $2p_z^1$ orbital forms (N-O)  $\mathrm{\pi }$-bond.
(4) In XeOF,, Xe-atom in its excited state $\left(5s^{2}5p^{3}5d^3\right)\text{ is }s{p}^3{d}^2$ hybridized. The singly filled five hybrid orbitals form $\mathrm{\sigma }$ -bonds with 4F atoms and O atom. The pure 5d orbital forms $\pi$ - bond with 2p orbital of O-atom.