Which of the following ions does not involve p $π$ — d $π$ bonding?

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${PO}_{4}^{3 -}$

${XeOF}_{4}$

${NO}_{3}^{-}$

${SO}_{3}^{2 -}$

answer is C.

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Detailed Solution

(1) The S-atom in the excited state (3s²3p³3d¹ ) has sp³ hybridization (sp³)² (sp³)¹ (sp³)¹(sp³)¹3d¹
The three hybrid orbitals form three (S-O) $σ$ -bonds and the 3d pure orbital gives (S-O) $π$ -bond.
(2) In ${PO}_{4}^{3 -}$ , P-atom in its excited state $(3 s^{1} 3 p^{3} 3 d^{1})$ is sp³ hybridized. Four hybrid orbitals forms (P-O) $σ$ -bonds whereas 3d¹ gives (P-O) $π$ -bond.

(3) In ${NO}_{3}^{-}$ N-atom is sp² hybridized as ${(s p^{2})}^{2} {(s p^{2})}^{1} {(s p^{2})}^{1} 2 p_{z}^{1}$

Completely filled sp’ hybrid orbital on N-atom donates an electron pair to the vacant 2p orbital of O atom to form dative bond. Other two hybrid orbitals form (N-O) $σ$ -bonds. The pure $2 p_{z}^{1}$ orbital forms (N-O) $π$ -bond.
(4) In XeOF,, Xe-atom in its excited state $(5 s^{2} 5 p^{3} 5 d^{3}) is s p^{3} d^{2}$ hybridized. The singly filled five hybrid orbitals form $σ$ -bonds with 4F atoms and O atom. The pure 5d orbital forms $π$ - bond with 2p orbital of O-atom.